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如果五個(gè)號(hào)碼為數(shù)組元素(1)到(5),正確的排序過(guò)程:
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對(duì)于i = 1至4
對(duì)于L = 1到5 - 如果A(L)(L +1)
N = A(L)
A(L),= A(L +1)
(L +1) =
結(jié)束如果下一頁(yè)l
接下來(lái),我
能夠到第一臺(tái)計(jì)算機(jī)來(lái)驗(yàn)證結(jié)果,然后分析程序。
給你一個(gè)最簡(jiǎn)單的冒泡排序代碼:
將三個(gè)數(shù)放到一個(gè)數(shù)組中。
a(0)=val(text1.text):a(1)=val(text2.text):a(2)=val(text3.text)
dim flag as Boolean,temp as Integer
for i = 0 to 2
flag = true
for j = 2 to 1
if a(j)a(j-1) then
temp = a(j-1)
a(j-1) = a(j)
a(j) = temp
flag = false
end if
next j
if flag then Exit For
next i
text4.text=a(0):text5.text=a(1):text6.text=a(2)
試試看:
For?i?=?LBound(moto)?To?UBound(moto)?-?1
For?j?=?LBound(moto)?To?UBound(moto)?-?1?-?i
If?moto(j)??moto(j?+?1)?Then
t?=?moto(j)
moto(j)?=?moto(j?+?1)
moto(j?+?1)?=?t
End?If
Next?j
Next?i
For?i?=?LBound(moto)?To?UBound(moto)
Print?moto(i);
Next?i